20y^2+68y-48=

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Solution for 20y^2+68y-48= equation:


Simplifying
20y2 + 68y + -48 = 0

Reorder the terms:
-48 + 68y + 20y2 = 0

Solving
-48 + 68y + 20y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-12 + 17y + 5y2) = 0

Factor a trinomial.
4((-4 + -1y)(3 + -5y)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-4 + -1y)' equal to zero and attempt to solve: Simplifying -4 + -1y = 0 Solving -4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1y = 0 + 4 -1y = 0 + 4 Combine like terms: 0 + 4 = 4 -1y = 4 Divide each side by '-1'. y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(3 + -5y)' equal to zero and attempt to solve: Simplifying 3 + -5y = 0 Solving 3 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -5y = 0 + -3 -5y = 0 + -3 Combine like terms: 0 + -3 = -3 -5y = -3 Divide each side by '-5'. y = 0.6 Simplifying y = 0.6

Solution

y = {-4, 0.6}

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